simplify sin theta cos 90 minus theta + 1 by 1 + tan square theta
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(sin theta ×sin theta +1)/1+tan2theta
sin2theta+1/1+tan2theta
sin2theta+1/sec2theta
tan2theata + cos square theta
sin2theta+1/1+tan2theta
sin2theta+1/sec2theta
tan2theata + cos square theta
Answered by
8
Answer:
1
Step-by-step explanation:
Hi,
Given expression is
sin(θ)*cos(90 - θ) + 1/(1 + tan²θ)
But we know that 1 + tan²θ = sec²θ,
Hence, given expression would become
sin(θ)*cos(90 - θ) + 1/sec²θ
Also, We know 1/secθ = cosθ,
hence 1/sec²θ = cos²θ,
hence given expression will be
sin(θ)*cos(90 - θ) + cos²θ
cos(90 - θ) = sin θ,
So, we can write given expression as
sin θ*sin θ + cos²θ
= sin²θ + cos²θ
= 1.
Hope, it helps !
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