Question

simplify sin theta.cos(90-theta)+1÷1+tan sqar theta

Answer 1

Ans.
$\sin\alpha\ \times cos(90 - \alpha ) + \frac{1}{1 + \tan^{2} \alpha } \\ = (sin \alpha \times sin \alpha ) + \frac{1}{sec^{2} \alpha } \\ = sin^{2} \alpha + cos^{2} \alpha \\ = 1.$