Question

simplify sin theta into cos of 90 minus theta + 1 by 1 + 10 square theta

Answer 1

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Ans.

${(sin \alpha \times cos(90 - \alpha ) )+} \frac{1}{1 + {tan}^{2} \alpha } \\ =(sin \alpha \times sin \alpha ) + \frac{1}{ {sec}^{2} \alpha } \\ = {sin}^{2} \alpha + {cos}^{2} \alpha \\ = 1$

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