simplify sin100°+cos100°
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Answered by
0
hi dude
Sin 100° + cos 100°
= sin100° + cos(90°+10°)
[cos 10° becomes sin 10°]
= sin100° + sin 10°
by the formula,
sin C + sin D = 2cos c+d/2 sin c - d / 2
= 2cos 100+10/2sin 100-10/2
= 2cos 110/2 sin 90/2
= 2cos55° + sin45°
= 2cos55° + 1/√2
=√2.√2 cos55° .1/√2
= √2cos55°
Sin 100° + cos 100°
= sin100° + cos(90°+10°)
[cos 10° becomes sin 10°]
= sin100° + sin 10°
by the formula,
sin C + sin D = 2cos c+d/2 sin c - d / 2
= 2cos 100+10/2sin 100-10/2
= 2cos 110/2 sin 90/2
= 2cos55° + sin45°
= 2cos55° + 1/√2
=√2.√2 cos55° .1/√2
= √2cos55°
Answered by
1
1 IS THE ANSWER BECAUSE FIRST SQUARE THA THAN YOU FIND
SIN^2 100 + COS ^2 100 ==> 1
ANSWER = 1
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