Question

simplify sin2 theta/ 1+cos 2 theta​

Answer 1

hope this may help you dear

Answer 2

Answer:

$\frac{ p {}^{2} }{1 + b {}^{2} }$

Step-by-step explanation:

$\sin(^{2} ) \div 1 + \cos( {}^{2} )$

$(p \div h)^{2} \div 1 +(b \div h) {}^{2}$

$(p {}^{2} \div h {}^{2}) \div \frac{1}{1} + (b {}^{2} \div h {}^{2} )$

$\frac{ p {}^{2} }{h {}^{2} } \times \frac{1 + h {}^{2} }{1 + b {}^{2} }$

$\frac{p {}^{2} }{1 + b {}^{2} }$