Question

simplify: sin3 theta-cos3 theta/sin theta-cos theta​

Answer 1

Answer:

use the identity (a^3+b^3)= (a+b)(a^2+b^2-ab)

sin^3A + cos^3A÷(sinA +cos ). + sinA.cosA

(sinA+cosA)(sin^2+cos^2 -sinA.cosA)÷ (sinA + cosA)+ sinA.cosA

or( sinA^2+cosA^2 -sinA.cosA) +sinA.cosA

1-sinA.cosA+sinA.cosA

1

Answer 2

Answer:

Hence LHS=RHS(PROVED)