Simplify-
Solution :
(1) 2a(b+c-a)²+2b(c+a-b)²+2c(a+b+c)²+2(a+b+c)[{a²-(b-c)²}+ {b²-(c–a)²}+{c²-(a+b)²}]
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a - b - c )². =[ a² + ( - b )² + ( -c )² ]². =a²+(-b)² +(-c)²+2a(-b)+2(-b)(-c)+2(-c)a. = a² + b² + ... (a +b+c)^2=a^2 + b^2 + c^2 + 2ab + 2bc + 2ac ... How do I prove that: a²+b²=1/2 ...
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