Question

simplify? solve the problem? ​

Answer 1

A number having 2 , 3 , 7 and 8 at its unit place is never a square number .

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Answer 2

Question number A:-

$\sqrt{80} - \sqrt{125} + \sqrt{20}$

$= \sqrt{16 \times 5} - \sqrt{5 \times 5 \times 5} + \sqrt{4 \times 5}$

$= 4 \sqrt{5} - 5 \sqrt{5} + 2 \sqrt{5}$

$= \sqrt{5} (4 - 5 + 2)$

$= \sqrt{5} \times 1$

$= \sqrt{5}$

Answer is √5

Question number B:-

$\sqrt{75} - \sqrt{48} + \sqrt{300} - \sqrt{147}$

$= \sqrt{5 \times 5 \times 3} - \sqrt{16 \times 3} + \sqrt{100 \times 3} - \sqrt{49 \times 3}$

$= 5 \sqrt{3} - 4 \sqrt{3} + 10 \sqrt{3} - 7 \sqrt{3}$

$= 4 \sqrt{3}$

Answer is 4√3

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