simplify solve the question
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it's easy just cross multiply n than I will get ur answer
I think you should do it on ur own
I think you should do it on ur own
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One way to solve this problem is by multiplying the denominators (x + 2) and (x - 2).
Let (x+4)/(x+2) = a
then,(x-1)/(x-2) = b
so our initial question becomes=> a - b
First we simplify a => a × (x-2)/(x-2) = a(x-2)/(x-2) = (x+4)(x-2)/(x+2)(x-2)
=>x^2-2x+4x-8/(x^2 - 2^2) => x^2+2x- 8/(x^2 - 4)
now we simplify b => b × (x+2)/(x+2) = (x-1)(x+2)/(x-2)(x+2)
=>(x^2+2x-1x-2)/(x^2 - 2^2) => (x^2+1x-2)/(x^2-4)
now we come back to our original question =>
a - b => (x^2+2x-8)/(x^2 - 4) - (x^2+1x-2)/(x^2-4)
the denominators are equal so we subtract the numerators (x^2+2x-8-x^2-x+2)/(x^2 - 2^2) =>
(x-6)/(x+2)(x-2) is your solution.
Let (x+4)/(x+2) = a
then,(x-1)/(x-2) = b
so our initial question becomes=> a - b
First we simplify a => a × (x-2)/(x-2) = a(x-2)/(x-2) = (x+4)(x-2)/(x+2)(x-2)
=>x^2-2x+4x-8/(x^2 - 2^2) => x^2+2x- 8/(x^2 - 4)
now we simplify b => b × (x+2)/(x+2) = (x-1)(x+2)/(x-2)(x+2)
=>(x^2+2x-1x-2)/(x^2 - 2^2) => (x^2+1x-2)/(x^2-4)
now we come back to our original question =>
a - b => (x^2+2x-8)/(x^2 - 4) - (x^2+1x-2)/(x^2-4)
the denominators are equal so we subtract the numerators (x^2+2x-8-x^2-x+2)/(x^2 - 2^2) =>
(x-6)/(x+2)(x-2) is your solution.
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