Question

Simplify tanA/secA-1 +tanA/secA+1​

Answer 1

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Answer 2

$\frac{tana}{seca - 1} + \frac{tana}{seca + 1} \\ \\ = tana( \frac{seca + 1 + seca - 1}{ {sec}^{2}a - 1 } ) \\ \\ = tana( \frac{2seca}{ {tan}^{2}a } ) \\ \\ = 2 \frac{seca}{tana} \\ \\ = 2 \times \frac{1}{cosa} \times \frac{cosa}{sina} \\ \\ = 2coseca$