Question

Simplify
$2 {}^{ - 1} + 3 {}^{ -1} + 4 {}^{ - 1}$
solve
​

Answer 1

${2}^{ - 1} + {3}^{ - 1} + {4}^{ - 1} \\ = \frac{1}{2} + \frac{1}{3} + \frac{1}{4} \\ = \frac{6 + 4 + 3}{12} = \frac{13}{12}$

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Answer 2

Answer:

The answer is $\frac{13}{12}$

Step-by-step explanation:

$2^{-1}+3^{-1}+4^{-1}$

$a^{-1}=\frac{1}{a}$

$\frac{1}{2}+\frac{1}{3}+\frac{1}{4}$

Least Common Multiplier of 2,3,4 is 12

$\frac{6+4+3}{12}$

= $\frac{13}{12}$