Math, asked by sanju4550, 1 year ago

Simplify:
2\log 3 - \frac{1}{2} \log 16 + \log 12

Answers

Answered by surajkj45
0
log3^2-log4+log12
log9×12/4
log 27
Answered by 23saurabhkumar
0

Answer:

2log3-\frac{1}{2}log16+log12=1.4313

Step-by-step explanation:

In the given question,

We have the equation given to us as,

2log3-\frac{1}{2}log16+log12

So now,

On using the properties of the logarithms like,

alogb=logb^{a}

and also the other property of the logarithms states to us that,

loga+logb=logab\\and,\\loga-logb=log\frac{a}{b}

So,

On using the properties of the logarithms same as stated above we get,

2log3-\frac{1}{2}log16+log12=log9-log4+log12\\=log\frac{108}{4}\\=log27\\=1.4313

Therefore, the final simplified solution of the given equation is given by,

1.4313.

Hence,

2log3-\frac{1}{2}log16+log12=1.4313

Similar questions
Math, 1 year ago