Question

simplify
$3 \sqrt{2} + \sqrt{18} - 1 \div 2 \sqrt{8} =$

Answer 1

Hello Friend ✋✋✋

Your answer.....

= ( 3√2 + 3√2 - 1 ) / 4√2

= (6√2 -1 )/4√2

Rationalising denominator......

= √2 × ( 6√2 -1 )/ ( √2 × 4√2 )

= ( 12 - √2 ) / 8

Hope it helps

Answer 2

May be the answer is.....
$\frac{3 \sqrt{2} + \sqrt{18} - 1 }{2 \sqrt{8} } \\ = \frac{3 \sqrt{2} + 3 \sqrt{2} - 1 }{2 \sqrt{8} } \\ = \frac{(6 \sqrt{2} - 1) }{2 \times 2 \sqrt{2} } \\ = \frac{(6 \sqrt{2 } - 1 )}{4 \sqrt{2} } \\ = \frac{4 \sqrt{2}( 6 \sqrt{2} - 1) }{32} \\ = \frac{48 - 4 \sqrt{2} }{32} \\ = \frac{4(12 - \sqrt{2} )}{32} \\ = \frac{(12 - \sqrt{2}) }{8}$
hope it helps...