Question

SIMPLIFY:
$( {48}^{ - 2} \times {64}^{ \frac{1}{2} }) \div {24}^{ - 1}$
$a. \: \: 12$
$b. \: \: 24$
$c. \: \: {12}^{ - 1}$
$d. \: \: none$
​

Answer 1

Step-by-step explanation:

$\tt \red{ \longmapsto( {48}^{ - 2} \times {64}^{ \frac{1}{2} }) \div {24}^{ - 1}}$

$\bf \pink{ \implies \: \frac{1}{ {48}^{2} } \times {64}^{ \frac{1}{2} } \div \frac{1}{24} }$

$\tt \purple{ \dashrightarrow \frac{1}{2304} \times \sqrt{64} \div \frac{1}{24} }$

$\tt \orange{ \implies \: \frac{8}{2304} \div \frac{1}{24} }$

$\bf \green{ \longmapsto \frac{8 \times 24}{2304} }$

$\tt \blue{ \dashrightarrow \frac{192}{2304} = \frac {\cancel{192}}{ \cancel{192} \times 12} }$

correct option is (c).

$12^{-1}$

$\boxed{\tt \pink{ \implies \frac{1}{12} }}$

Answer:

$\boxed{\huge{\mathbb\pink{REFERR \:TO\: THE\:\: ATTACHMENT }}}$

Step-by-step explanation:

hope it help you.

thanks

Answer 2

Answer:

find the smallest number by which 81 must be divided to obtain a perfect cube

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