Question

Simplify:
$4st(s - t) - {6s}^{2} (t - t) - {3t}^{2} ( {2s}^{2} - s) + 2st(s - t)$
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Answer 1

The simplified form for 4st ( s - t ) - 6s² ( t - t ) - 3t² ( 2s² - s ) + 2st ( s - t) = 3st { 2 ( s - t ) - t ( 2s - 1 ) }

• The given expression is :

4st ( s - t ) - 6s² ( t - t ) - 3t² ( 2s² - s ) + 2st ( s - t)

Or, 4st ( s - t ) - 6s² × 0 - 3t².s ( 2s - 1 ) + 2st ( s - t )

[ Since t - t = 0 ]

Or, 4st ( s - t ) - 0 - 3t².s ( 2s - 1 ) + 2st ( s - t )

[ Since multiplication of a term with 0 is 0 ]

Or, 4st ( s - t ) - 3t².s ( 2s - 1 ) + 2st ( s - t )

Or, 4st ( s - t ) + 2st ( s - t ) - 3st² ( 2s - 1 )

Or, 2st ( s - t ) ( 2 + 1 ) - 3st² ( 2s - 1 )

[ Taking 2st ( s - t ) as the common term between 4st ( s - t ) and 2st ( s - t ) ]

Or, 3.2st ( s - t ) - 3st² ( 2s - 1)

[ Brining 2 + 1 = 3 in front ]

Or, 6st ( s - t ) - 3st² ( 2s - 1 )

Or, 3st { 2 ( s - t ) - t ( 2s - 1 ) }