Question

simplify
${8}^{\frac{2}{3} } - \sqrt{9} \times {10}^{0} + {144}^{ \frac{1}{2} }$
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Answer 1

$= {8}^{\frac{2}{3} } - \sqrt{9} \times {10}^{0} + {144}^{ \frac{1}{2} } \\ = {({2}^{3} )}^{ \frac{2}{3} } - {9}^{ \frac{1}{2} } \times 1 + {({12}^{2} )}^{ \frac{1}{2} } \\ = {2}^{3 \times \frac{2}{3} } - {3}^{2 \times \frac{1}{2} } \times 1 + {12}^{2 \times \frac{1}{2} } \\ = {2}^{2} - 3 \times 1 + 12 \\ = 4 - 3 + 12 = 16 - 3 = 13$

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Answer 2

Step-by-step explanation:

$\bf \underline{Solution-}$

${8}^{ \frac{2}{3} } - \sqrt{9} ( {10)}^{0} + \bigg( \frac{1}{144} \bigg) ^{ - \frac{1}{2} }$

$= ( {8}^{2} {)}^{ \frac{1}{3} } - 3(1) + \frac{1}{ \bigg( \frac{1}{144} \bigg) ^{ \frac{1}{2} } }$

$= \sqrt[3]{64} - 3 + \frac{1}{ \left \{ \bigg( \frac{1}{12} \bigg) ^{2} \right \}^{ \frac{1}{2} } }$

$= \sqrt[3]{4 \times 4 \times 4} - 3 + \frac{1}{\bigg( \frac{1}{12} \bigg)}$

$= 4 - 3 + 12$

$= \boxed{13 \: \bf{Ans.}}$