simplify
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Answered by
0
Step-by-step explanation:
(a
2
+b
2
)x
2
−2(ac+bd)x+(c
2
+d
2
)=0 has equal roots.
Therefore, discriminant =0
Thus [2(ac+bd)]
2
+4(a
2
+b
2
)(c
2
+d
2
)
⇒a
2
c
2
+b
2
d
2
+2ac.bd=a
2
c
2
+a
2
d
2
+b
2
c
2
+b
2
d
2
⇒(ad−bc)
2
=0$
⇒ad−bc=0
⇒ad=bc
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