Question

Simplify: $\frac{(2^5)^6 \times (3^3)^2}{(2^6)^5 \times (3^2)^3}$

Answer 1

hope this helps...........

Answer 2

Answer= 1

Solution:

$\frac{(2^5)^6 \times (3^3)^2}{(2^6)^5 \times (3^2)^3} \\ \\ we \: know \: that \\ \\ ( { {x}^{a} })^{b} = {x}^{ab} \\ \\ = \frac{ {2}^{30} \times {3}^{6} }{ {2}^{30} \times {3}^{6} } \\ \\ = {2}^{30} \times {3}^{6} \times {2}^{ - 30} \times {3}^{ - 6} \\ \\ = {2}^{30 - 30} \times {3}^{6 - 6} \\ \\ = {2}^{0} \times {3}^{0} \\ \\ = 1 \times 1 \\ \\ \frac{(2^5)^6 \times (3^3)^2}{(2^6)^5 \times (3^2)^3} = 1$
Because anything power zero is equal to 1.

Hope it helps you.