Question

simplify:-
$\frac{2 + \sqrt{3} }{2 - \sqrt{3} } - \frac{2 - \sqrt{3} }{2 + \sqrt{3} }$
please solve this​

Answer 1

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$

Step-by-step explanation:

$\sf\pink{ \frac{2 + \sqrt{3} }{2 - \sqrt{3} } - \frac{2 - \sqrt{3} }{2 + \sqrt{3} } } \\ \sf\pink{ = > \frac{(2 + \sqrt{3} )(2 + \sqrt{3} ) - (2 - \sqrt{3} )(2 + \sqrt{3} )}{(2 - \sqrt{3} )(2 + \sqrt{3} )} } \\ \sf\pink{ = > \frac{ {(2 + \sqrt{3} )}^{2} - {(2 - \sqrt{3} )}^{2} }{ {2}^{2} - { \sqrt{3} }^{2} } } \\ \sf\pink{ = > \frac{(4 + 3 + 2 \sqrt{3 }) - (4 + 3 - 2 \sqrt{3} ) }{4 - 3} } \\ \sf\pink{ = > \frac{4 + 3 + 2 \sqrt{3 } - 4 - 3 + 2 \sqrt{3} }{1} } \\ \sf\pink{ = > 7 - 7 + 4 \sqrt{3} } \\ \sf\pink{ = > 4 \sqrt{3} } \\ \large\boxed{ \fcolorbox{blue}{purple}{hope \: it \: help \: you}}$