Simplify:
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Solution:
*****************************************
We know the Exponential laws :
i ) ( a^m )ⁿ = a^mn
ii ) a^m/a^n = 1/a^n-m
****************************************
Now ,
[ ( 5^-3 )² × 3⁴ ]/[ (3^-2)^-3 × ( 5³ )^-2 ]
= [ 5^-6 × 3⁴ ]/ [ 3^6 × 5^-6 ]
= 3⁴/3^6
= 1/3^6-2
= 1/3²
= 1/9
••••••
*****************************************
We know the Exponential laws :
i ) ( a^m )ⁿ = a^mn
ii ) a^m/a^n = 1/a^n-m
****************************************
Now ,
[ ( 5^-3 )² × 3⁴ ]/[ (3^-2)^-3 × ( 5³ )^-2 ]
= [ 5^-6 × 3⁴ ]/ [ 3^6 × 5^-6 ]
= 3⁴/3^6
= 1/3^6-2
= 1/3²
= 1/9
••••••
Answered by
0
hope this helps.............
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