Question

Simplify:
$\frac{ \sqrt{35} + \sqrt{50} + \sqrt{72} }{ \sqrt{18} + \sqrt{98} }$
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Answer 1

Answer :-

$\frac{ \sqrt{35} + \sqrt{50} + \sqrt{72} }{ \sqrt{18} + \sqrt{98} } \\ \\ \frac{ \sqrt{35} + 5 \sqrt{2} + 6\sqrt{2} }{ 3\sqrt{2} + 7\sqrt{2} } \\ \\ \frac{ \sqrt{35} + 11 \sqrt{2} }{ 10\sqrt{2} } \\ \\ \frac{ (\sqrt{35} + 11 \sqrt{2}) \times \sqrt{2} }{ 10\sqrt{2} \times \sqrt{2} } \\ \\ \frac{ \sqrt{70} + 22}{20}$

hope this will help you