simplify.
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By using the formula,
[a³ + b³ = a3 + b3 + 3a2b + 3ab2]
By substituting in the above equation, we get
p3 – (p + 1)3 = p³ – (p³ + 3p² + 3p + 1)
= p³ – p³ – 3p² – 3p – 1
= – 3p² – 3p – 1
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