CBSE BOARD X, asked by Anonymous, 6 months ago

Simplify :-
 \red{\bf \dfrac{3}{216^{\frac{-2}{3}}} + \dfrac{2}{256^{\frac{-3}{4}}} + \dfrac{2}{243^{\frac{-1}{5}}} }

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Answers

Answered by Anonymous
1674

♣ Qᴜᴇꜱᴛɪᴏɴ :

\sf{\dfrac{3}{216^{\tfrac{-2}{3}}}+\dfrac{2}{256^{\tfrac{-3}{4}}}+\dfrac{2}{243^{\tfrac{-1}{5}}}}

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♣ ᴀɴꜱᴡᴇʀ :

242

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♣ ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴꜱ :

\dfrac{3}{216^{\tfrac{-2}{3}}}+\dfrac{2}{256^{\tfrac{-3}{4}}}+\dfrac{2}{243^{\tfrac{-1}{5}}}

\sf{=\dfrac{3}{\left(6^3\right)^{\tfrac{-2}{3}}}+\dfrac{2}{\left(4^4\right)^{\tfrac{3}{4}}}}+\dfrac{2}{\left(3^5\right)^{\tfrac{-1}{5}}}}

\sf{=\dfrac{3}{\left(6\right)^{\tfrac{-6}{3}}}+\dfrac{2}{\left(4\right)^{\tfrac{4}{4}}}}+\dfrac{2}{\left(3\right)^{\tfrac{-5}{5}}}}

\sf{=\dfrac{3}{(6)^{-2}}+\dfrac{2}{(4)^{-3}}+\dfrac{2}{(3)^{-1}}}

\sf{=3 \times 6^{2}+2 \times 4^{3}+2 \times 3^{1}}

\begin{array}{l}\sf{=108+128+6} \\\\\\\sf{=242}\end{array}

Answered by SnowFlakeBoy
4

 \huge \rm \red{\underline{\underline{Answer :- }}}

The answer is 242 ;)

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