simplify

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Solution :

=
=√[(√2)²+1²+2√2×√1]
= √(√2+1)²
= √2 + 1
Therefore,

= $\sqrt2 + 1 $
••••
=
=√[(√2)²+1²+2√2×√1]
= √(√2+1)²
= √2 + 1
Therefore,
= $\sqrt2 + 1 $
••••
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