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1. (√3 + √11)² (√3 + √11)²
= (a+b)² = a² + 2ab + b²
a) = (√3 + √11)² = (√3)² + 2 x √3 x √11 + (√11)²
= 3 + 2√33 + 11
= 14 + 2√33
b) = (√3 + √11)² = (√3)² + 2 x √3 x √11 + (√11)²
= 3 + 2√33 + 11
= 14 + 2√33
Therefore = (√3 + √11)² (√3 + √11)²
= (14 + 2√33) (14 + 2√33)
= (14 + 2√33)²
Hope it will help you ^_^
But i think your question is (√3 + √11)² (√3 - √11)²
If it is here is the answer =
2. (√3 + √11)² (√3 - √11)²
= (a+b)² = a² + 2ab + b²
= a) = (√3 + √11)² = (√3)² + 2 x √3 x √11 + (√11)²
= 3 + 2√33 + 11
= 14 + 2√33
=(a-b)² = a² - 2ab + b²
b) = (√3 - √11)² = (√3)² + 2 x √3 x √11 + (√11)²
= 3 - 2√33 + 11
= -8 + 2√33
Therefore (√3 + √11)² (√3 - √11)²
= (14 + 2√33 ) (-8 + 2√33)
= -112 + (2√33)²
I hope the 2nd answer is correct hope it will help you ^_^
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