Question

simplify...
$\sqrt{3} + \sqrt{7} \div \sqrt{27} + \sqrt{63} - \sqrt{28} - \sqrt{48}$
please answer this friends...

Answer 1

Hey your answer is (5+√21)/2

Answer 2

$Given : \sqrt{3} + \frac{ \sqrt{7} }{ \sqrt{27} } + \sqrt{63} - \sqrt{28} - \sqrt{48}$

$= \ \textgreater \ \sqrt{3} + \frac{ \sqrt{7} }{3 \sqrt{3} } + \sqrt{7 * 3^2} - \sqrt{7 * 2^2} - \sqrt{3 * 2^4}$

$= \ \textgreater \ \sqrt{3} + \frac{ \sqrt{7} }{3 \sqrt{3} } + \sqrt{7} * \sqrt{3^2} - \sqrt{7} * \sqrt{2^2} - \sqrt{3} * 2^2$

$= \ \textgreater \ \sqrt{3} + \frac{ \sqrt{7} }{3 \sqrt{3} } + 3 \sqrt{7} - 2 \sqrt{7} - 4 \sqrt{3}$

$= \ \textgreater \ \frac{ \sqrt{7} }{3 \sqrt{3} } - 2 \sqrt{7} + 3 \sqrt{7} - 3 \sqrt{3}$

$= \ \textgreater \ \frac{ \sqrt{7} }{3 \sqrt{3} } + \sqrt{7} - 3 \sqrt{3}$

$= \ \textgreater \ \frac{ \sqrt{7} }{3 \sqrt{3} } * \frac{ \sqrt{3} }{ \sqrt{3} } + \sqrt{7} - 3 \sqrt{3}$

$= \ \textgreater \ \frac{ \sqrt{7} \sqrt{3} }{3 \sqrt{3} \sqrt{3} } + \sqrt{7} - 3 \sqrt{3}$

$= \ \textgreater \ \frac{ \sqrt{21} }{9} + \sqrt{7} - 3 \sqrt{3}$




Hope this helps!