Question

Simplify
$\sqrt[4]{16} - 6 \sqrt[3]{343} + 18 \sqrt[5]{243} - \sqrt{196}$

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Answer 1

Answer:

here your answer

2-6(7)+18(3)-14

2-42+54-14

56-56

0

Answer 2

Answer:

0

Step-by-step explanation:

We have given 1 equation in the question which we have to simplify

For solving this question we just need to have the good knowledge of the numbers below 10 and we must know the cube root and square root of the numbers below10

So the given equation is

$\sqrt[4]{16}-6\times\sqrt[3]{343}+18\times\sqrt[5]{243}-\sqrt{196}$

Therefore

$\sqrt[4]{16}=2\\\sqrt[3]{343}=7\\\sqrt[5]{243}=3\\\sqrt{196}=14$

=$2-6\times7+18\times3-14$

Therefore our final answer would be

=0