Math, asked by imaduddinsiddiqui631, 9 months ago

Simplify:
 \sqrt{63 }  - 5 \sqrt{28}  + 11 \sqrt{7}

Answers

Answered by harshkvardhan
3

Answer:

12\sqrt{7}

Step-by-step explanation:

ATQ,

\sqrt{63} -5\sqrt{28} +11\sqrt{7}

First, we separate the value of the radicals into a set of prime numbers.

\sqrt{(3 \times 3 \times 7)} -5\sqrt{(2 \times 2 \times 7)} +11\sqrt{7}

Now, if you know, a radical symbolizes a square root of a number. And a square of a number is a number multiplied by itself.

Here, there are two pairs of identical numbers inside two of the radicals, which mean the root operation can be applied on them. So we remove the square of the number from the radical, leaving only the plain number.

3\sqrt{7} -5\sqrt{7} +11\sqrt{7}

Now the radicals on each of the terms are identical, so we can add these terms while the radical remains unaffected.

\sqrt{7} (3-2+11)

We get the final answer as:

12\sqrt{7}

Answered by deepikapaliwal202
0

Answer:

the answer is 4√7 as when we will simplify the roots then we will get the answer

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