Question

simplify the above question​

Answer 1

Answer:

bahut hard h

nhi hoo payega

sorry

Answer 2

Answer:

[(a/a-x)+(b/b-x)+(c/c-x)] / [(3/x)-(1/x-a)-(1/x-b)-(1/x-c)] =

[(a/a-x)+(b/b-x)+(c/c-x)] / [(3/x)+ (1/a-x)+(1/b-x)+(1/c-x))] We did this by factoring out

[a(b-x)(c-x) + b(a-x)(c-z)+c(a-x)(b-x)]/[(a-x)(b-x)(c-x)] = Numerator

3[(a-x)(b-x)(c-x)+x(b-x)+x(x-a)(x-c)+x(x-a)(x-c)]/x[(a-x)(b-x)(c-x) = Denominator