Math, asked by payal32367, 11 months ago

simplify the equation and verify your answer 3 X + 1 upon X + 5 is equals to 6 x minus 7 upon 2 X + 1​

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Answered by harsh312138
3

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Answered by ShreyaSingh31
22

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Given equations :-

\bf\large\frac{3x + 1}{x + 5} = \bf\large\frac{6x - 7}{2x + 1}

To solve this equation, we will cross multiply the LHS to RHS of the equation and find the value of x

\bf\large\frac{3x + 1}{x + 5} = \bf\large\frac{6x - 7}{2x + 1}

Cross multiplying,

( x + 5) (6x - 7) = (2x + 1) ( 3x + 1)

Multiplying each brackets,

x ( 6x - 7) 5 (6x - 7) = 2x (3x +1) 1 (3x + 1)

Writing the multliplicative product,

6x² - 7x + 30x - 35 = 6x² + 2x + 3x + 1

Getting the like terms together,

+6x² - 6x² - 7x + 30x - 2x - 3x = 1 + 35

Terms with opposite signs, will get cancelled.

23x - 5x = 36

On further subtracting on LHS,

18x = 36

Now, keeping the x on the LHS, we will perform further operation,

x = \large\frac{36}{18}

On dividing by 18, we get value of x

x = 2

•°• The required value of x for the equation is 2

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