Question

Simplify
the expresion
A'BCD+AB'CD+ABC'D+ABCD'
(using K-MAP)​

Answer 1

Explanation:

A'BCD + AB'CD' + AB'CD + ABC'D + ABCD' + ABCD = (A'BCD + ABCD) + (AB'CD' + AB'CD + ABCD' + ABCD) + (ABC'D + ABCD)

Now use A+A'=1 (etc)

A'BCD + ABCD = (A'+A)BCD = BCD

AB'CD' + AB'CD + ABCD' + ABCD = AC (as explained by William)

ABC'D + ABCD = ABD