Math, asked by gehnavijayvargiya, 16 days ago

Simplify the expression.

12a+[3ab−2{5ab^2+(a−b)+(a−b+c)}]

Answers

Answered by misraarav
2

a2 – b2 = (a – b)(a + b)

(a+b)2= a2 + 2ab + b2

a2 + b2 = (a – b)2 + 2ab

(a – b)2 = a2 – 2ab + b2

(a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc

(a – b – c)2 = a2 + b2 + c2 – 2ab – 2ac + 2bc

(a + b)3 = a3 + 3a2b + 3ab2 + b3

(a – b)3 = a3 – 3a2b + 3ab2 – b3

Answered by pratham2010singhal
1

Answer:

8a + 3ab -10ab^2+4b-2c

Step-by-step explanation:12a+[3ab−2{5ab^2+(a−b+a-b+c)}

12a+[3ab−2{5ab^2+2a-2b+c}

12a+[3ab−10ab^2-4a+4b-2c}

8a + 3ab -10ab^2+4b-2c

cuemath answer

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