Simplify the expression.
12a+[3ab−2{5ab^2+(a−b)+(a−b+c)}]
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Answered by
2
a2 – b2 = (a – b)(a + b)
(a+b)2= a2 + 2ab + b2
a2 + b2 = (a – b)2 + 2ab
(a – b)2 = a2 – 2ab + b2
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc
(a – b – c)2 = a2 + b2 + c2 – 2ab – 2ac + 2bc
(a + b)3 = a3 + 3a2b + 3ab2 + b3
(a – b)3 = a3 – 3a2b + 3ab2 – b3
Answered by
1
Answer:
8a + 3ab -10ab^2+4b-2c
Step-by-step explanation:12a+[3ab−2{5ab^2+(a−b+a-b+c)}
12a+[3ab−2{5ab^2+2a-2b+c}
12a+[3ab−10ab^2-4a+4b-2c}
8a + 3ab -10ab^2+4b-2c
cuemath answer
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