Question

simplify the expression​

Answer 1

Answer:

LHS: ab + (ac)' + ab'c(ab+c)

Apply Demorgan's Law: (ac)' = a' + c'.

= ab + a' + c' + ab'c

= (ab+ab'c) + (a'+c')

= a(b+b'c) + (a'+c')

Apply the dual of distributive law: (b+b'c) = (b+b')(b+c)

= a(b+b')(b+c) + (a'+c')

= ab + ac + a' + c'

= (ab+a') + (ac+c')

= (a+a')(b+a') + (a+c')(c+c')

= b+a'+a+c'

= b+(a'+a)+c'

= b+c'+1 = 1 = RHS

if it is the solution tgan mark me as brainliest

Answer 2

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THANK YOU?!