Math, asked by blue27942, 8 months ago

Simplify the expression 5 (x^2+xy)+3-xy and find its value when x = 5 and y = -2​

Answers

Answered by EmmaWatson01
1

Answer:

According to the Question we will first simplify then multiply also accoring to the rule of BODMAS

Step-by-step explanation:

5(x^2 + xy) + 3-xy

5x^2 + 5xy + 3-xy

5x^2 + 5xy - xy + 3

5x^2 + 4xy + 3

now x= 5, y= -2

5(5)^2 + 4(5)(-2) + 3

5(25) + 4(-10) + 3

125 + (-40) + 3

125 - 40 + 3

= 80

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