Simplify the expression so there is only one power for each base. (3x2)^5 / (3^2x2^3)
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(3×2)^5/(3^2×2^3)
=(3^5)(2^5)/(3^2)(2^3)
=(3^5)/3^2 × (2^5)/(2^3)
=(3^3)×(2^2)
=(3^5)(2^5)/(3^2)(2^3)
=(3^5)/3^2 × (2^5)/(2^3)
=(3^3)×(2^2)
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