Math, asked by madhav467633, 5 months ago

simplify the expressions and find their values of p=1,q=1,r=2
a. 5p^2-6q^2-7r^2+6p^2-5q^2+2r^2​

Answers

Answered by ankitnandi200593
2

Answer:

5p {}^{2}- 6q {  }^{2}- 7r {}^{2}  + 6p {}^{2}- 5q {}^{2} + 2r {} ^{2}  = 5  \times  1 {}^{2}  - 6 \times 1 {}^{2} - 7 \times 2 {}^{2}  + 6 \times 1 {}^{2}- 5 \times 1 {}^{2} + 2 \times 2 {}^{2}  =  - 20.(p = 1.q = 1r = 2)

Answered by trientasheraine
3

\huge\purple{\boxed{\tt{}{Answer:}}}

\large\color{pink}{-20}

\large\purple{\boxed{\tt{}{Solution:}}}

5p^2-6q^2-7r^2+6p^2-5q^2+2r^2

= 5(1)^2-6(1)^2-7(2)^2+6(1)^2-5(1)^2+2(2)^2

= 5- 6-28+6-5+8

\large\color{lime}{= -20}

\huge\purple{\boxed{\tt{}{Explanation:}}}

substitute the value of p,q and r

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