Question

simplify the following
1) 1/7*2/9-3/14*1/9+2/9*1/14
please answer me fast​

Answer 1

Answer:

Answer:

\frac{1}{7}\times \frac{2}{9}- \frac{3}{14}\times \frac{1}{9}+ \frac{2}{9}\times \frac{1}{14}=\frac{1}{42}71×92−143×91+92×141=421

Step-by-step explanation:

Given : Expression  \frac{1}{7}\times \frac{2}{9}- \frac{3}{14}\times \frac{1}{9}+ \frac{2}{9}\times \frac{1}{14}71×92−143×91+92×141

To find : Solve the expression using identities?

Solution :

Expression  \frac{1}{7}\times \frac{2}{9}- \frac{3}{14}\times \frac{1}{9}+ \frac{2}{9}\times \frac{1}{14}71×92−143×91+92×141

Applying distributive identity, ab+ac=a(b+c)ab+ac=a(b+c)

Taking \frac{1}{9}91 common from whole expression,

=\frac{1}{9}[\frac{2}{7}- \frac{3}{14}+\frac{2}{14}]=91[72−143+142]

Taking LCM,

=\frac{1}{9}[\frac{4-3+2}{14}]=91[144−3+2]

=\frac{1}{9}\times \frac{3}{14}=91×143  

=\frac{1}{3\times14}=3×141

=\frac{1}{42}=421    

Therefore, \frac{1}{7}\times \frac{2}{9}- \frac{3}{14}\times \frac{1}{9}+ \frac{2}{9}\times \frac{1}{14}=\frac{1}{42}71×92−143×91+92×141=421

Answer 2

Answer:

== 1/42

Step-by-step explanation:

2/63 - 3/126 +2/126

3/126

1/42