Question

Simplify
the following
​

Answer 1

Answer:

Hope it'll help you....

Answer 2

$</p><p> \sf \rightarrow \quad \bigg( \dfrac{1}{2} \bigg)^{ - 3} + \bigg( \dfrac{1}{3} \bigg)^{ - 2} + \bigg( \dfrac{1}{4} \bigg)^{ - 1} \\ \\ \sf \quad \bigg( \dfrac{1}{a^{m}} \bigg) = a^{-m} \\ \\ \sf \rightarrow \quad {2}^{3} + {3}^{2} + {4}^{1} \\ \\ \sf \rightarrow \quad 8 + 9 + 4 \\ \\ \sf \rightarrow \quad 21</p><p>$