simplify the following
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=> 7√3. – 2√5 – 3√2.
√10 + √3. √6 + √5. √15 + 3√2
=> Rationalising the denominator.
=> 7√3(√10 – √3) – 2√5(√6–√5)
(√ 10 + √3)(√10 – √3). (√6–√5)(√6+√5)
– 3√2 (√15–3√2).
(√15–3√2)(√15+3√2)
=> 7√30 – 21 – 2√30 – 10 – 3√30 – 6
7 1 –3
=> √30 – 3 – 2√30 + 10 + √30 – 2
=> 5..
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