Question

simplify the following: 2(x+2)+3(x²+3x+2)-4(x³-7)​

Answer 1

Answer:

x³ + 4x² - x - 4)/( x² +3x - 4)

numerator : (x³ + 4x² - x - 4)

= x³ -x + 4x² - 4

= x(x² -1) + 4(x² -1)

= (x +4)(x² -1)

= (x + 4)(x - 1)(x + 1)

denominator : (x² + 3x - 4)

= x² + 4x - x - 4

= x(x + 4) -(x + 4)

= (x - 1)(x + 4)

now, put this in above expression.

(x +4)(x -1)(x + 1)/(x -1)(x + 4)

=(x + 1)

Answer 2

Step-by-step explanation:

2(x+2)+3(x2+3x+2)-4(x3-7)

2x+4+3x2+9+6-4x3+27

2x+46+4x2+4x3

NOTICE THE 4X2 IS SQUARE SAME WITH 4X3

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