simplify the following 28+[6+{3×(27÷9 by 5)}]
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We can solve this by Bodmas formula :-
28+[6+{3×(27÷9/5)}]
=28+[6+{3×(27×5/9)}] (9/5is reciprocal)
=28+[6+{3×15}]
=28+[6+45]
=28+[51]
=79
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