Question

SIMPLIFY THE FOLLOWING:


3/2y^2(y^2-1)-3/4y(y^3-1)+1/4y^2(y^2+y)​

Answer 1

Answer: 3/4y - 3/2y^2 + 1/4y^3 + y^4

Step-by-step explanation:

3/2y^2(y^2-1)-3/4y(y^3-1)+1/4y^2(y^2+y)

3/2y^4 - 3/2y^2 - 3/4y^4 + 3/4y +1/4y^4 + 1/4y^3

6-3+1/4y^4 - 3/2y^2 + 3/4y + 1/4y^3

3/4y - 3/2y^2 + 1/4y^3 + y^4

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Answer 2

Simplified value is $\frac{1}{4} y^4 + \frac{1}{4} y^3 - \frac{3}{2} y^2 +\frac{3}{4} y$

Given:

$3/2y^2(y^2-1)-3/4y(y^3-1)+1/4y^2(y^2+y)​$

To Find:

To get the value which is simplified from the above question

Solution:

$3/2y^2(y^2-1)-3/4y(y^3-1)+1/4y^2(y^2+y)​$

= $\frac{3}{2} y^4 - \frac{3}{2} y^2 - \frac{3}{4} y^4 + \frac{3}{4} y + \frac{1}{4} y^4 + \frac{1}{4}y^3$

= $y^4( 3/2 - 3/4 + 1/4 ) + 1/4 y^3 - 3/2 y^2 +3/4y$

Upon Simplifying ,

We get,

$\frac{1}{4} y^4 + \frac{1}{4} y^3 - \frac{3}{2} y^2 +\frac{3}{4} y$

Hence, the simplified value is $\frac{1}{4} y^4 + \frac{1}{4} y^3 - \frac{3}{2} y^2 +\frac{3}{4} y$