Math, asked by suryagis300780, 5 hours ago

simplify the following
8√15÷2√3​

Answers

Answered by spacelover123
15

Question

Simplify the following -: 8√15 ÷ 2√3

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Answer

To simplify this we will first write the expression in p/q form.

⇒ 8√15 ÷ 2√3

\dfrac{8\sqrt{15}}{2\sqrt{3}}

Now we will write all of the terms in the simplest form.

\dfrac{8\sqrt{15}}{2\sqrt{3}}

\dfrac{8\times \sqrt{5\times 3}  }{2\times \sqrt{3}}

We will use this formula → \sqrt{x \times y }= \sqrt{x} \times \sqrt{y}

\dfrac{8\times \sqrt{5\times 3}  }{2\times \sqrt{3}}

\dfrac{8\times \sqrt{5}\times \sqrt{ 3 } }{2\times \sqrt{3}}

We will cross out √3 from numerator and denominator since they are common.

\dfrac{8\times \sqrt{5}\times \sqrt{ 3 } }{2\times \sqrt{3}}

\dfrac{8\times \sqrt{5} }{2}

\dfrac{8\sqrt{5}}{2}

⇒ 4√5

∴ 8√15 ÷ 2√3​  = 4√5

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Answered by Anonymous
0

Answer:

★᭄ꦿ᭄Answer★᭄ꦿ᭄

Question

Simplify the following -: 8√15 ÷ 2√3

_______________________________

Answer

To simplify this we will first write the expression in p/q form.

⇒ 8√15 ÷ 2√3

\dfrac{8\sqrt{15}}{2\sqrt{3}}

Now we will write all of the terms in the simplest form.

\dfrac{8\sqrt{15}}{2\sqrt{3}}

\dfrac{8\times \sqrt{5\times 3}  }{2\times \sqrt{3}}

We will use this formula → \sqrt{x \times y }= \sqrt{x} \times \sqrt{y}

\dfrac{8\times \sqrt{5\times 3}  }{2\times \sqrt{3}}

\dfrac{8\times \sqrt{5}\times \sqrt{ 3 } }{2\times \sqrt{3}}

We will cross out √3 from numerator and denominator since they are common.

\dfrac{8\times \sqrt{5}\times \sqrt{ 3 } }{2\times \sqrt{3}}

\dfrac{8\times \sqrt{5} }{2}

\dfrac{8\sqrt{5}}{2}

⇒ 4√5

∴ 8√15 ÷ 2√3  = 4√5

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