simplify the following :- ¡- (a-b) (a+b)+(b-c) (b+c)+(c-a) (c+a)=0
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Answer:
Answer:
Step-by-step explanation:
(a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a),
=(a²-b²)+(b²-c²)+(c²-a²),
=(a²-b²+b²-c²+c²-a²),
In this case, each variable cancels it's negative version.
= 0
NOW, THAT'S THE CORRECT ANSWER.
Step-by-step explanation:
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