Math, asked by kriti279, 2 months ago

simplify the following :- ¡- (a-b) (a+b)+(b-c) (b+c)+(c-a) (c+a)=0​

Answers

Answered by JyotishmanPhatowali
1

Step-by-step explanation:

 = ((a - b)( a+ b)) +( (b  -  c)(b + c)) + (( c - a)( c + a))

 = ( {a})^{2}  -  ({b})^{2}  + ( {b})^{2}  - ( {c})^{2}  + ( {c})^{2}  -  ({a})^{2}

  = {a}^{2}  -  {a}^{2}  +  {b }^{2}  -  {b}^{2}  +  {c}^{2}  -  {c}^{2}

 = 0

HENCE PROVED

Answered by Anonymous
1

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