Question

Simplify the following algebraic expression and then find the value: 3x² - y² - z² - x² + 2y² + 4z², when x = 1, y = -2 and z = 2. ​

Answer 1

Answer:

3x² - y² - z² - x² + 2y² + 4z²

= 2x² + y² + 3z²

@ (1,-2,2)

We get,

2+4+12 = 16