Question

simplify the following and verify the result for the given values ii.(7x2y-3z2)(x+y+z);x=1,y=1,z=-1​

Answer 1

Answer:

x=1,y=1,z=-1 (7x ^ 2y-3z ^ 2) (x + y + z)

put in the value

7^(2+3^2)(1+1-1)

7^25(1)

=7^25

Answer 2

Answer -

(7x2-3z2) (x+y+z)

= 7x2(x+y+z) + (-3z2)(x+y+z)

=( 7x3y+7x2y2+7x2yz ) + ( -3xz2 -3yz2-3z3)

= 7x3y+7x2y2+7x2yz-3xz2-3yz2-3z3

verifying

LHS - 7*1*1*1*1 +7*1*1*1*1+7*1*1*1*-1-3*1*-1*-1-3*1*-1*-1-3*-1*-1*-1

= 7+7+-7-3-3-(-3)

= 7+7-7-3-3+3  

= 4

RHS - (7*1*1*1-3*-1*-1) (1+1+-1)

= 4

HOPE IT WILL  HELP YOU