Simplify the following boolean expression into simple one
a.c + b(b`+c). (a`+b.c`)
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Answer:
a*c + b(b`+c)*(a`+b*c`)
Step 1:-
Use BODMAS in this, we get
ac+ bb`+bc*(a`+bc)
Step 2
Multiply the other bracket, we get
aa`c+ abc²+ bb`a`+ b²b`c+ bca`+ (bc)²
Step 3
Take commons if required
a(a`c+ bc²) + b(b`a`+ bb`c+ca`) +(bc)²
The above is the required answer.
harshashra258:
but i need it in simple form you have made it more complicated
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