simplify the following Boolean function to minimum number of literals ( input variables) a) f=ABC+ABD+ABC+CD+BD
b)F=A(A+B+C)+(A+B+C).(A+B+C).(A+B+C)
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a) f=ABC+ABD+CD+BD+ABC
=(ABC+ABC)+D (AB+B)+CD
=ABC+BD+CD
b) F=A (A+B+C)+(A+B+C)
= A+ B+ C
=(ABC+ABC)+D (AB+B)+CD
=ABC+BD+CD
b) F=A (A+B+C)+(A+B+C)
= A+ B+ C
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