Math, asked by Anonymous, 10 months ago

Simplify the following:-
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Answered by Anonymous
2

Answer:

3 \sqrt{3}  + 2 \sqrt{27}  +  \frac{7}{ \sqrt{3} }  =  \\  \\  =  > 3 \sqrt{3}  + 2 \times 3 \sqrt{3}  +  \frac{7}{ \sqrt{3} }  \\  \\  =  >  \frac{9 + 18 + 7}{ \sqrt{3} }  \\  \\  \\  =  >  \frac{34}{ \sqrt{3} }  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\  \\ 2. \\  \\  =  >  \frac{ \sqrt{24} }{8}  +  \frac{ \sqrt{54} }{9}  \\  \\  =  >  \frac{2 \sqrt{6} }{8}  +  \frac{3 \sqrt{6} }{9}  \\  \\  =  >  \frac{ \sqrt{6} }{4}  +  \frac{ \sqrt{6} }{3}  \\  \\  =  >  \frac{3 \sqrt{6 } + 4 \sqrt{6}  }{12}  \\  \\  =  >  \frac{ \sqrt{6} (4 + 3)}{12}  \\  \\  =  >  \frac{7 \sqrt{6} }{12}

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Answered by kumarpratyush656
5

Step-by-step explanation:

2)\ \frac{ \sqrt{24} }{8}   +  \frac{ \sqrt{54} }{9}  \\  \\\frac{2 \sqrt{6} }{8}  +  \frac{3 \sqrt{6} }{9}  \\ \\ \frac{ \sqrt{6} }{4}   +  \frac{ \sqrt{6} }{3}  \\  \\\frac{3 \sqrt{6} + 4 \sqrt{6}  }{12}  \\ \\ \frac{7 \sqrt{6} }{12}

\\\\\\1)3 \sqrt{3}  + 2 \sqrt{27}  +  \frac{7}{ \sqrt{3} }  \\\\ 3 \sqrt{3}  + 6 \sqrt{3}  +   \frac{7 \sqrt{3} }{3}  \\ \\ \sqrt{3} (3 + 6 +  \frac{7}{3} ) \\ \\ \sqrt{3} ( \frac{9 + 18 + 7}{3} ) \\ \\ \sqrt{3}  \times  \frac{34}{3}  \\ \\ \frac{34 \sqrt{3} }{3}

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